a train is starting from rest moves with uniform acceleration of 0.2meterpersecondsfor five minutes calculate the speed and distance travelled in this time
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u=0 m/s
a=0.2 ms^-2
t=5 min=5×60=300 sec
v=?
s=?
v=u+at
=0+(0.2)(300)
=60m/s
s=ut+1/2at^2
=0+(0.5)(0.2)(300)^2
=(0.1)(90000)
=9000 m=9Km
a=0.2 ms^-2
t=5 min=5×60=300 sec
v=?
s=?
v=u+at
=0+(0.2)(300)
=60m/s
s=ut+1/2at^2
=0+(0.5)(0.2)(300)^2
=(0.1)(90000)
=9000 m=9Km
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