a train is travel at speed of 90 km per hour . brakes are applied so as to produce a uniform acceleration of - 0.5 m second square find how are the train will go before it is brought to rest
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hey dear
here is your answer
given data :
initial velocity (u) = 90 km/hr or 25 m/s
acceleration (a) = -0.5 m/s²
final velocity (v) = 0
to find : distance
here we go
by using third equation of motion
v² = u²+2as
0 = (25)²+2*(-0.5)*s
625 = 1s
s = 625 meter
hope it helps :)
here is your answer
given data :
initial velocity (u) = 90 km/hr or 25 m/s
acceleration (a) = -0.5 m/s²
final velocity (v) = 0
to find : distance
here we go
by using third equation of motion
v² = u²+2as
0 = (25)²+2*(-0.5)*s
625 = 1s
s = 625 meter
hope it helps :)
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