A train is traveling at a speed of 25m/s.brakes are applied.so as to produce a uniform acceleration of -0.5m/s square .find how far the train will go before it is brought to rest
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Answer:
625m
Explanation:
v^2-u^2=2*a*s
0-25^2=2*-0.5*s
=625m
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final velocity (v) = 0
Initial velocity (u) = 25m/s
acceleration (a) = -0.5m/s square
Distance (S) = ?
by law of motion,
v squared = u squared + 2aS
0 = 625 + 2*-0.5*S
-625 = -1*S
S = -625/-1
Thus, S = 625 meters
Therefore, the train will travel 625 meters before it is brought into a state of rest ..
Hope it helps mate ..!
Initial velocity (u) = 25m/s
acceleration (a) = -0.5m/s square
Distance (S) = ?
by law of motion,
v squared = u squared + 2aS
0 = 625 + 2*-0.5*S
-625 = -1*S
S = -625/-1
Thus, S = 625 meters
Therefore, the train will travel 625 meters before it is brought into a state of rest ..
Hope it helps mate ..!
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