a train is traveling at a speed of 60 km per hour brakes are applied so as to produce a uniform acceleration of -0.5 m per second find how far dream will go before is brought to rest
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Given,
Intial velocity(u) =60km/hr
Final velocity(v) =0km/hr
Accleration(a)=-0.5m/sec or 1.8km/hr
Time taken (t)
Now,
a=(v-u) /t
Therefore t=(v-u)/a
t=(0-60)/(-1.8)
=-60/-1.8
=60*10/18
=600/18
=33.33hours
Or 33 hours(approx)
Intial velocity(u) =60km/hr
Final velocity(v) =0km/hr
Accleration(a)=-0.5m/sec or 1.8km/hr
Time taken (t)
Now,
a=(v-u) /t
Therefore t=(v-u)/a
t=(0-60)/(-1.8)
=-60/-1.8
=60*10/18
=600/18
=33.33hours
Or 33 hours(approx)
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