A train is traveling at a speed of 90 km h(power -1).Brakes r applied so as to produce a uniform accelaration of -0.5 m s (power -2).Find how far the train will go before it is brought to rest.
Answers
Answered by
7
u = 90 kmph = 90 * 5/18 m/sec = 25 m/sec
a = -0.5 m/sec²
v = 0 as the train comes to rest.
the equation of motion is
v² = u² + 2 a s
0 = 25² - 2 * 0.5 * s
s = 625 meters
a = -0.5 m/sec²
v = 0 as the train comes to rest.
the equation of motion is
v² = u² + 2 a s
0 = 25² - 2 * 0.5 * s
s = 625 meters
Answered by
0
Answer:
this is your answer
hope this are helpful to you
Attachments:
Similar questions