A train is traveling at a speed of 90kmperh .brakes are applied so as to produce a uniform acceleration of _0.5m persec .find how far the train will go before it is broght to rest.
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initial speed, u = 90 km/h = 90 x (1000/3600) m/s = 25 m/s
final speed, v = 0 m/s
uniform acceleration, a = -0.5 m/s2
Using equation of motion: v2 = u2 + 2as
We have: 0 = (25)^2 + 2x(-0.5)xs
s = 625 m
[s: distance traveled by the train after the brakes are applied and before it is finally brought into rest]
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