Question

a train is traveling at the speed of 108 kmh^-1 brakes are applied so as to produce a uniform acceleration of -0.5ms^-2 find how far the train will go before it is brought to rest.

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Answer 1

Explanation:

Given,

u=108km/h=

60×60

108×1000

=30m/s

a=−1m/s

2

v=0m/s

From 3rd equation of motion,

2as=v

2

−u

2

−2×1×s=0

2

−30×30

s=

−2×1

−30×30

s=450m