Question

a train is travelling at a sleed of 90 km per hour . brakes are applied so as to produce a uniform accerlation of 0.5 m per second square. find how far train will go before it is brought to rest....answer if u can....dare.....​

Answer 1

Answer:

625m

Explanation:

90kmph = 25m/s

using the equation, v^2 - u^2 = 2as

where v= 25 m/s

u= 0 m/s (since the train comes to rest).

therefore, 625 = 2 x 0.5 x s

x = 625 m.