A train is travelling at a speed o
f 90 km /h.brake are applied so as to produce a uniform acc of -0.5 m/ssq find distance
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Answer is 625
Explanation:
GIVEN, INITIAL SPEED =90 KM/H
90×(1000/3600)=25 m/s
FINAL SPEED=0 m/s
ACCELARATION =-0.5 m/sq
BY USING THE THIRD EQUATION OF MOTION
vsq=usq + 2as
0sq=(25)sq + 2×-0.5×s
0=625 -1s
1s=625
s=625/1
s=625
Therefore,distance is 625
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