Question

A train is travelling at a speed of 25m/s. Brakes are applied so as to produce a uniform acceleration of -0.5m/s. Find how far the train will go before it is brought to rest.​

Answer 1

Answer-

u=25m/s a= -0.5m/s2 t=50s s=?

from, s = ut + 1/2at2

s= 25*50 + 1/2*(-0.5)*50*50

s = 1250 - 625

s = 625m

Answer 2

A train is travelling at a speed of 25 m/s. Later on, brakes are applied so as to produce a uniform acceleration of -0.5m/s².

So, Initial velocity (u) is 25 m/s and final velocity (v) is 0 m/s.

Also, acceleration is -0.5 m/s² (retardation or deceleration).

We have to find how far the train will go before it is brought to rest. Means, we have to find the distance (s).

Now,

v² - u² = 2as

Substitute the known values

→ (0)² - (25)² = 2 × (-0.5) × s

→ 0 - 625 = -1.0s

→ -625 = -s

→ s = 625 m

Therefore, the train will go 625 m before it is brought to rest.