Question

A train is travelling at a speed of 25m/s. Brakes are applied so as to produce a uniform acceleration of -0.5m/s. Find how far the train will go before it is brought to rest.​

Answer 1

Answer:

25m

Explanation:

initial velocity (u) = 25m/s

final velocity (f) = 0m/s

acceleration (a) = -0.5m/s

displacement (s) = s

Then,

v² = u²+2*a*s

0² = 25 + 2*(-0.5)*s

0² = 25 + (-s)

0 = 25 - s

s = 25 + 0

s = 25m

Answer 2

Answer:

625mtrs

Explanation:

v²=u²+2as

here v=0    and acceleration is -ve  then it becomes 2as=u²

s=u²/2a

s=25²÷(2×0.5)

s=625mtr