Question

A train is travelling at a speed of 50kmph when the driver decided to apply brakes with a

retardation speed of 18m/s2

. Find the time required to stop the train.​

Answer 1

u = 50km/h = 50*5/18 m/s = 13.88 m/s

v = 0 m/s

a = -18 m/s^2

t = ?

v = u+at

0 = 13.88+(-18)t

-13.88 = -18t

13.88/18 = t

t = 0.77 sec

Hence, Time taken by train to stop is 0.77 sec

Answer 2

Given : A train is travelling at a speed of 50kmph when the driver decided to apply brakes with a retardation speed of 18m/s²

To Find  : the time required to stop the train

Solution:

Train initial Speed = 50 km/hr

1 km = 1000 m

1hr = 3600 Secs

Hence speed in m /s  = 50 * 1000 / 3600

= 500 / 36

= 250 / 18  m/s

a = - 18 m/s²

v = 0   at rest

v = u + at

=> 0  = 250/18  + (-18) t

=> t = 250/18²

=> t = 0.7716 sec

time required to stop the train.​  = 0.7716 sec

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