Question

A train is travelling at a speed of 55 km/hr . A person is running on the roof of the train in the opposite direction with the speed 1 m/s . Calculate the speed of the person with respect to a stationery observer on the platform.


any plz answer asap​

Answer 1

$\red{\bold{\sf{Speed\:of \:train\:w.r.t\: platform(V_{tp})=55kmph}}}$

$\red{\bold{\sf{Speed\:of \:man\:w.r.t.\:train(V_{mt})=1ms^{-1}}}}$

$\red{\bold{\sf{Speed\:of \:man\:w.r.t.\: platform(V_{mp})=?}}}$

${\large{\tt{V_{mp}=V_{tp}-V_{mt}}}}$

${\large{\tt{V_{mp}=55kmph-1ms^{-1}}}}$

${\large{\tt{V_{mp}=55kmph-(1×\frac{18}{5})kmph}}}$

${\large{\tt{V_{mp}=\frac{257}{5}kmph=}}}$$\underline{\red{\large{\tt{51.4kmph}}}}$