A train is travelling at a speed of 60 km / h . Brakes are applied so as to produce a uniform acceleration of -0.5 m / s2 . Find how far the train will go before it is brought to rest .
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answer is 277.8 m or 0.277 k8
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Initial velocity, u = 60 km/h
= 60×1000/3600 m/s¹
= 60000/3600 m/s¹
= 600/36 m/s¹
= 16.67 m/s
Final velocity, v = 0 m/s
Acceleration, a = - 0.5 m/s²
Distance travelled =?
Using, = v² = v² - u²/2a
S = v² - u²/ 2a
= 0² - 16.67²/2(-05)
= 227.889 m/s².
Therefore, Train will go 277.889 m before it brought to rest.
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