Question

A train is travelling at a speed of 60 km/ h. Brakes are applied so as to produce a uniform acceleration
of −0.5 m /s 2 . Find how far the train will go before it is brought to rest.

Answer 1

final velocity = 0m/s

initial velocity = 60×5/12

= 25m/s

t = v- u/a

t= 0-25/-0.5

Solve this equation and you will be find t.

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Answer 2

Answer:

Explanation:

Initial velocity, u = 60 km/h

= 60×1000/3600 m/s¹

= 60000/3600 m/s¹

= 600/36 m/s¹

= 16.67 m/s

Final velocity, v = 0 m/s

Acceleration, a = - 0.5 m/s²

Distance travelled =?

Using, = v² = v² - u²/2a

S = v² - u²/ 2a

= 0² - 16.67²/2(-05)

= 227.889 m/s².

Therefore, Train will go 277.889 m before it brought to rest.