Question

a train is travelling at a speed of 60 km per hour brakes are applied so as to produce a uniform acceleration of -2.5 metre per second square find how far the train will go before it is brought to rest​

Answer 1

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Answer 2

Answer:

The train will cover a distance of 55.57m before it is brought to rest.

Explanation:

Given that,

A train is travelling at a speed of 60km/h brakes are applied so as to produce a uniform acceleration of -2.5m/s2.We are required to find the distance covered by train before it is brought to rest.For that we use a kinematic equation of motion as shown below

${v}^{2} - {u}^{2} = 2as$

Here,

v=Final velocity=0

u=Initial velocity=60km/h

$u = 60 \times \frac{5}{18} = 16.67 ms {}^{ - 1}$

And the acceleration is

$a = - 2.5m {s}^{ - 2}$

Substituting these in above equation,we get

${0}^{2} - {16.67}^{2} = 2 \times - 2.5 \times s = > s = \frac{ - {16.67}^{2} }{ - 5} = 55.57 \: m$

Therefore,the train will cover a distance of 55.57m before it is brought to rest.

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