Question

A train is travelling at a speed of 85km/h breakes are applied so as to produce uniform accerlation of 0.8m/sec find how for the train before it go to rest

Answer 1

Answer:

The distance travelled is 348.395m.

Explanation:

Given here,

Initial velocity, u= 85km/h

= [(85×1000)/3600]m/s

= 23.61m/s

Final velocity, v=0 (The body goes to rest)

Acceleration, a=-0.8m/s

Distance travelled, s=?

We know,

v^2=u^2+2as

0=u^2+2as

-2as=u^2

s=-(u^2/2a)

s=-[557.4321/(-1.6)]

s=348.395

The distance travelled is 348.395m.