Question

A train is travelling at a speed of 90 km/ h . Brakes are applied so as to produce a uniform acceleration of - o.5 m/ s . Find how far the train will go before it is brought to rest.​

Answer 1

Answer:

625m

Explanation:

v=90kmph

=90×5/18=25m/s

v^2-u^2=2as

625-0=2×0.5×s

s=625m

Answer 2

Solution,

Here, we have

Initial velocity of the trolley, u = 0 (As starts from rest)

Acceleration of the trolley, a = 0.02 m/s²

Time taken by the trolley, t = 3 seconds

To Find,

Final velocity of the trolley, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of the trolley is 0.06 m/s.