Question

A train is travelling at a speed of 90 km/h. Brakes are applied So as to produce a uniform acceleration of - 0.5 m/s ^(2). Find how far will the train go before it is brought to rest.

I have got its answer as 625 m. Is that is right ​

Answer 1

Answer:

Answer:

U=90kmh=25m/s

v=0

v

{v {}^{2} - {u }^{2} } =2asv 2 −u 2 =2as

{25 {}^{2} - 0}^{2} = 2( - 0.5)s25 2 −0 2=2(−0.5)s

s=625m

distance = 625m

Explanation:

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Answer 2

Answer:

Hey mate ur answer is correct .......

here is its solution