Question

A train is travelling at a speed of 90 km/h.
Brakes are applied, so as to produce a uniform
acceleration of -0.5 m/s2. Find how far the train
will go before it is brought to rest?

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Answer 1

Answer:

u=90km/h

=25m/s

v=0

a=-0.5m/s^2

Explanation:

2as=v^2-u^2

2*(-0.5)*s=(0)^2-(25)^2

-1*s=0-625

s=-625/-1

s=625m

Thus, the distance travelled is 625m.

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Answer 2

Answer:

Explanation:

Given:-

Initial speed of the train, u = 90 km/h = 25 m/s

The final speed of the train, v = 0

Acceleration = - 0.5 m/s²

To Find:-

Distance acquired

Formula to be used:-

Third equation of motion:

v² = u² + 2 as

Solution:-

Putting all the value, we get

v² = u² + 2as

⇒ (0)² = (25)² + 2 × (- 0.5) s

⇒ s = 625 m

Hence, The train will cover a distance of 625 m before coming to rest.