A train is travelling at a speed of 90 km/h breaks are applied so as to produce a uniform acceleration of 0.5m/s^2. find how far the train will go before it is brought to rest.
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initial velocity u =90m/s
Final velocity v =0m/s. (brought to rest)
acceleration a=0.5m/s²
let the distance travel be 'S'
using Newton law of motion,
v²-u²=2aS
(90)²-0=2x0.5xS
S=8100m
S=8.1 km
Final velocity v =0m/s. (brought to rest)
acceleration a=0.5m/s²
let the distance travel be 'S'
using Newton law of motion,
v²-u²=2aS
(90)²-0=2x0.5xS
S=8100m
S=8.1 km
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