A train is travelling at a speed of 90 km/hr. brakes are applied so as to produce a uniform acceleration of - 0.5ms^-2. find how far the train will go before it brought to rest?
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Answer:
90 km/hr in m/s is 5/18*90=25 m/s
Explanation:
given: v=0 a=-0.5 m/s u=25 m/s. distance (s)=?
by third equation of motion v^2-u^2=2(a)(s) 0^2-25^2=2(-0.5)(s) 0-625=-1(s) -625=-1(s) s=625 metres
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