Physics, asked by JacksonHandsome, 4 months ago

A train is travelling at a speed of 90 km per hour–¹. brakes are applied so as to produce a uniform acceleration of -0.5 minute per second–². find how far the train will go before it is brought to rest.​

Answers

Answered by sunnysunnyraj1999
22

Answer:

Given Final velocity (v) = 50 m/s

Initial velocity (u) = 30 m/s

Acceleration (a) = 2.5 m/s

2

We know v = u + at

∴ 50 = 30 + 2.5 t

⇒ 50 - 30 = 2.5 t

2.5

20

= t or 8 = t

∴ Time taken to accelerate = 8 seconds

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Explanation:

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Answered by thebrainlykapil
808

\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}

  • A train is travelling at a speed of 90 km per hour–¹. brakes are applied so as to produce a uniform acceleration of -0.5 minute per second–². find how far the train will go before it is brought to rest.

\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}

  • Intial Speed of train ( u ) = \sf\green{90km \:  {h}^{ - 1}  }

\qquad \quad {:} \longrightarrow \sf{\sf{90 \:  \times  \:  \frac{5}{18}   }}

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ \: Intial \: Speed \: = \:  25m \:  {s}^{ - 1}   }}}

  • Final Speed ( v ) = \sf\green{ {0}m \: s^{ - 1}  }
  • Acceleration ( a ) = \sf\green{ {0.5}m \: s^{ - 2}  }

\\  \\  \\  \\  \\

\large\underline{ \underline{ \sf \maltese{ \: To \: Find :- }}}

  • Distance Covered ( S ) ?

━━━━━━━━━━━━━━━━━━━━━━━━━

\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}

\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\:   {v}^{2}  \:  -  \:  {u}^{2}  \:  =  \: 2aS  }} }\\ \\\end{gathered}\end{gathered}\end{gathered}

 \qquad \quad {:} \longrightarrow \sf{\sf{ \frac{ {v}^{2 }  \:  -  \:  {u}^{2} }{2a}   }} \\  \\  \\

\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{{0}^{2 }  \:  -  \:  {(25)}^{2} }{2\:  \times  \: ( \:  - 0.5 \: )} }}\\  \\  \\

\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Distance \: (\: S \: ) \: = \: 625m }}}

━━━━━━━━━━━━━━━━━━━━━━━━━

\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Distance \: = \underline {\underline{ 625m}}}\\\end{gathered}\end{gathered}

━━━━━━━━━━━━━━━━━━━━━━━━━

\large\underline{ \underline{ \sf \maltese{ \: More \: to \: Know :- }}}

  • Motion is an integral part of this universe everybody around us in his motion from the motion to the tiniest electron in their orbit around the nucleus or to the motion to the entire universe around its centre.
  • Uniform Velocity :- A body said to be possess uniform velocity, if it undergoes equal displacement in equal intervals of time

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