Question

a train is travelling at a speed of 90 km per hour brakes are applied so as to produce a uniform acceleration of -0.5 metre per second find out for the train will go before it is brought to rest

Answer 1

Answer:

625 m

Explanation:

Speed of train = 90km/h

= 90 * 5/18 m/s [ 1 Km/H = 5/18 m/s]

= 25m/s

Acceleration = -0.5 m/s^2

Final Velocity = 0 [ Since the object is coming to rest]

Using 3rd eq.

v^2 = u^2 + 2as

0 = 625 -s

s = 625 m

Therefore , the train travels 625 m before coming to rest.....

Hope it helps you.......

Answer 2

Answer:

90km/hr = 25 m/s

v=u+at

v=0 as it comes to rest

0= 25 -0.5t

0.5t=25

t=50s

it will stop in 50 s and the dist it will travel in 50 s will be

s=ut +at²/2

s= 25×50 -0.25×2500

s=1250-625

s= 625m