Question

a train is travelling at a speed of 90 km per hour brakes are applied so as to produce uniform acceleration of -0.5 km per hour find how far the train will go before its brought to rest​

Answer 1

u =90km/hr 90×5/18=25m/s

a=-0.5ms

v=0

v^2-u^2=2as

=>v^2=u^2+2as

=(25) ^2+2(-0.5) ×s

=625(-1) ×s

=625m/s

the train will cover a (s) of 625m before it comes to rest