a train is travelling at a speed of 90 km per hour brakes are applied so as to produce a uniform acceleration of - 0.5 m per second square find how far the train ago before it is brought to rest.
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s1(u)(initial speed)= 90 km/hr=90*5/18=25 m/s
s2(v)(final speed)=0m/s
-a=0.5 m/s 2
distance-S
2aS=(v*v)-(u*u)
S=(v*v)-(u*u)/2a
= 0-625/2*(-0.5)
=-625/-1
=625m
s2(v)(final speed)=0m/s
-a=0.5 m/s 2
distance-S
2aS=(v*v)-(u*u)
S=(v*v)-(u*u)/2a
= 0-625/2*(-0.5)
=-625/-1
=625m
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