Question

A train is travelling at a speed of 90 km per hour .Brakes are applied so as to produced a uniform acceleration of -0•5 m s-2. Find how far the train will go before it is brought to rest?

Answer 1

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Answer 2

Answer:

Therefore, the train will go 635m  before it is brought to rest.

Step-by-step explanation:

The initial speed is "u"=90km per hour=$90{\times}\frac{5}{18}=25ms^{-1}$. Since, the breaks applied, therefore v=0.

Now, using the third equation of the motion,

$v^{2}=u^{2}+2as$

$0=(25)^{2}+2(-0.5)(s)$

$0=625-s$

$s=625m$

Therefore, the train will go 635m  before it is brought to rest.