Question

a train is travelling at a speed of 90 km per hour break are apply so as to produce a accelleration of -0.5 ms-2 find how much far the train will go before its brought to rest​

Answer 1

Answer:

the answer is in photo

Explanation:

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Answer 2

Answer:

ok I got it

here is your answer :-

u - 120m/ s

a - -0.5

t - 2 seconds

therefore,. s = ut + 1/2 at^2

= 239 m