Question

A train is travelling at a speed of 90 km per hour .breaks are applied so as to produce a uniform acceleration of 0. negative 5 metre per second . find thow far the train will go before it goes to rest?

Answer 1

v=u+at 90km/hr=90*1000/3600m/s=25m/s

0=25-0.5t

t=50s

s=ut+0.5at^2

s=25*50-0.5*0.5*50^2

s=1250-625

s=625m