Question

A train is travelling at a speed of 90 km per hour the brakes are applied so as to produce a uniform acceleration of -0.5m/s^2. Find how far does the train go before it is brought to rest.

Answer 1

speed = u= 90 km/hr = 90 ×5/18 = 25 m /sec

Acceleration = -1/2 m/s²

v = final velocity =0

By formula

v² = u² + 2as

0 = 25² + 2 × -1/2 × s

0 = 625 - s

s = 625 m

so before getting at rest

it goes upto 625 m