A train is travelling at a speed of 90 km per hour the brakes are applied so as to produce a uniform acceleration of -0.5m/s^2. Find how far does the train go before it is brought to rest.
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speed = u= 90 km/hr = 90 ×5/18 = 25 m /sec
Acceleration = -1/2 m/s²
v = final velocity =0
By formula
v² = u² + 2as
0 = 25² + 2 × -1/2 × s
0 = 625 - s
s = 625 m
so before getting at rest
it goes upto 625 m
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