A train is travelling at a speed of 90 km pet hour. Brakes are applied so as to produce a uniform accreleration of -0.5 in m/ s square. Find how far the train will go before it is brought to rest.
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Answered by
1
Initial velocity, u = 90 km/h
= 90 × 1000/ 3600 ms¹
= 90000/ 3600
=900/36 ms¹
= 25 ms¹
Final velocity, v = 0 m/s
Acceleration, a. = -0.5 ms²
Distance travelled =?
Using, = v² = u² + 2as
S = v² - u²/ 2a
S = 0² - 25²/ 2 (-0.5)
S = 625m
Therefore, Train will go 625 m before it brought to rest.
Answered by
7
Answer:
Initial velocity, u = 90 km/h
= 90 × 1000/ 3600 ms¹
= 90000/ 3600
=900/36 ms¹
= 25 ms¹
Final velocity, v = 0 m/s
Acceleration, a. = -0.5 ms²
Distance travelled =?
Using, = v² = u² + 2as
S = v² - u²/ 2a
S = 0² - 25²/ 2 (-0.5)
S = 625m
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