Question

A train is travelling at a speed of 90km h^-1. Brakes are applied so as to produce a uniform acceleration of -0.5ms ^-2. find how far the train will go before it is brought to rest.

Answer 1

Answer:

please give me 20 thanks

Explanation:

i give me 40 thanks

Answer 2

Initial velocity of the train- 90 km/h or 25 m/s

Final velocity- 0 m/s

Acceleration- 0.5 m/s²

So,

2as= v²-u² [Here s is distance]

2(0.5)(s)= 0²-25²

s= -625= 625 m [Distance can never be negative]