A train is travelling at a speed of 90km h-1. Brakes are applied so as to produce a uniform acceleration of -0.5 m/s-2.Find how far tha train will go before it is brought to rest?
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Answer:
As per the third motion equation, v2-u2=2as
Therefore,
distance traveled by the train (s) =(v2-u2)/2a
s = (02-252)/2(-0.5) meters
= 625 meters
The train must travel 625 meters at an acceleration of -0.5 ms-2 before it reaches the rest position.
Explanation:
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