Question

A train is travelling at a speed of 90km h-1 breakes are applied so as to produce a uniform acceleration of -0.5ms-2.find how far the. Train will go before is brought to rest

Answer 1

Answer:

Explanation:

Train will travel 625 m before it is bought to rest.

According to the question the speed of the train is = 90 km/h

Retardation of the train = -0.5 m/s²

Final velocity = 0 m/s

By using the equation we can find distance covered by train before it is bought to rest:

=> v² = u² + 2as

By putting the value we get

=> 0² = 25² + 2(-0.5)s

=> 0 = 625 - 1s

=> s = 625

Therefore, Train will travel 625 m before it is bought to rest.

Answer 2

Answer:-

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