Question

A train is travelling at a speed of 90km/ h. Brakes are applied so as to produce a uniform accerleration of -0.5m/s. Find how far the train will go before it is brought to rest.

Answer 1

initial velocity (u) = 90 km/h = 25m/s
accelaration (a) = -0.5
final velcoity (v) = 0
time (t) = ?
distance (s) = ?


v = u +at
0 = 25 + (-0.5)t
-25 = -0.5 t
t = 50 sec

now,
s = ut +1/2(a){t(sqaured)}
s = 25*50 + 0.5(-0.5){50*50}
s = 1250 - 625
s = 625 metres

Answer 2

Answer:

Explanation:

Hope it will help you