A train is travelling at a speed of 90km/h.brakes are applied so as to produce a uniform acceleration 0.5m/s².find how far will the train go before it is brought to rest?
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When brakes are applied, the uniform acceleration of the train is -0.6 m/s². We have to find the distance covered by the train before it come to rest. So, the train will go 520.8 m before coming to rest. Hence, this is the required solution
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Answer:
Explanation:
v = 0 m/s
u = 90×5/18 = 25m/s
a= - 0.5 m/s² (retardation)
v² - u² = 2as
0 - 25² = - 2× 0.5× s
s= 625 m
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