Question

A train is travelling at a speed of 90km/h. Brakes are applied so its speed decreases to 54km/h in 3sec. Find the acceleration.​

Answer 1

Answer:

a = (v - u)/t

u = 90×5/18 = 25m/s

v = 54 × 5/18 = 15m/s

a = (15-25)/3

a = (-10)/3

a = -10/3

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Answer 2

Explanation:

Initial velocity of the train (u) = 90 km/hr

Final velocity of the train (v) = 54 km/hr

Time = 3 s

Acceleration = Final velocity - initial velocity/time

= (v -u) / t

= ( 54 - 90 ) /3

= -36/3

= -12

Therefore, the acceleration of the train is

-12 m/s²