# A train is travelling at a speed of 90km/h breaks are applied so the acceleration is 0.5 m/s2 . How far the train will go before it brought to rest

## Answers

Answered by

6

first convert into m/s

u=90×5/18

=25m/s

a=-0.5m/s2

distance=?

v=0

t=v-u/a

=0-25/-0.5

=50seconds

S=ut+a(t)2

S=25×50+1/2×-0.5×(50)2

S=625m

u=90×5/18

=25m/s

a=-0.5m/s2

distance=?

v=0

t=v-u/a

=0-25/-0.5

=50seconds

S=ut+a(t)2

S=25×50+1/2×-0.5×(50)2

S=625m

Answered by

6

hope it helped........

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