Question

A train is travelling at a speed of 90km/h breaks are applied so the acceleration is 0.5 m/s2 . How far the train will go before it brought to rest

Answer 1

first convert into m/s
u=90×5/18
=25m/s
a=-0.5m/s2
distance=?
v=0
t=v-u/a
=0-25/-0.5
=50seconds
S=ut+a(t)2
S=25×50+1/2×-0.5×(50)2
S=625m

Answer 2

hope it helped........