Question

a train is travelling at a speed of 90km/h.breaks are applied so as to produce a uniform acceleration of-0.5in m/s square . find how far the train will go before it is brought to rest ​

Answer 1

Answer:

s=625m

Explanation:

Here initial speed(u) = 90 Km/h = 90(5/18) = 30(5/6) = 5*5=25 m/s

Uniform acceleration(a) = -0.5 m/s²

Since the train is brought to rest

Final speed = 0 m/s

From v²-u²=2as

0²-(25)² = 2(-0.5)(s)

-625=-s

s=625m