Physics, asked by digitalaryan8, 8 months ago

a train is travelling at a speed of 90km/hr . brakes are applied to produce a uniform retardation of 1 m/s² . find how the train will go before coming to rest​

Answers

Answered by jatinkumar26
0

Answer:

90sec

Explanation:

as the final speed will become 0 so v=0m/sec

a = (v-u)/t

-1 = (0-90)/t

-1×t = -90

-t = -90

t=90seconds

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Answered by Anonymous
0

Answer:

hope this helps you my dear friend

Explanation:

ANSWER

Given that,

Acceleration a=−0.5m/s

2

Speed v=90km/h=25m/s

Using equation of motion,

v=u+at

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Finally train will be rest so, final velocity,v=0

0=25−0.5t

25=0.5t

t=

0.5

25

t=50 sec

Again, using equation of motion,

S=ut+

2

1

at

2

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

s=25×50−

2

1

×0.5×(50)

2

s=625 m

So, the train will go before it is brought to rest is 625 m.

this is the answer of your question

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