a train is travelling at a speed of 90km/hr . brakes are applied to produce a uniform retardation of 1 m/s² . find how the train will go before coming to rest
Answers
Answer:
90sec
Explanation:
as the final speed will become 0 so v=0m/sec
a = (v-u)/t
-1 = (0-90)/t
-1×t = -90
-t = -90
t=90seconds
plz mark as brainliest
Answer:
hope this helps you my dear friend
Explanation:
ANSWER
Given that,
Acceleration a=−0.5m/s
2
Speed v=90km/h=25m/s
Using equation of motion,
v=u+at
Where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Finally train will be rest so, final velocity,v=0
0=25−0.5t
25=0.5t
t=
0.5
25
t=50 sec
Again, using equation of motion,
S=ut+
2
1
at
2
Where, s = distance
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Where S is distance travelled before stop
s=25×50−
2
1
×0.5×(50)
2
s=625 m
So, the train will go before it is brought to rest is 625 m.
this is the answer of your question
please mark me as branilist