A train is travelling at a speed of 90km/hr. Brakes are applied so as to produce a uniform acceleration of - 0.5m/s2. Find how far the train will go before it is brought to rest.
Answers
Answered by
2
Answer:
625 m
Explanation:
Given that,
Acceleration a=−0.5m/s
Speed v=90km/h=25m/s
Using equation of motion,
v=u+at
Where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Finally train will be rest so, final velocity,v=0
0=25−0.5t
25=0.5t
t= 0.5
25
t=50 sec
Again, using equation of motion,
S=ut+
2
1
at
2
Where, s = distance
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Where S is distance travelled before stop
s=25×50−
2
1
×0.5×(50)
2
s=625 m
Similar questions