A train is travelling at a speed of 90km/hr Brakes are applied so as
to produce a uniform acceleration of 0.5 m/s2
find how far the train
will go before it is brought to rest.
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1
Answer:
625
Explanation:
Finally train will be rest so, final velocity,v=0
0=25−0.5t
25=0.5t
t=0.525
t=50 sec
Again, using equation of motion,
S=ut+21at2
Where, s = distance
v = final velocity
u = initial velocity
a = acceleration
t = time
Put the value into the equation
Where S is distance travelled before stop
s=25×50−21×0.5×(50)2
s=625 m
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