Question

A train is travelling at a speed of 90km/hr. brakes are applied so as to reduce a uniform acceleration of -0.5m/s2 find how far the train will go before it is brought to rest

Answer 1

u=90*5/18

=25m/s

v =0(at rest)

a=-0.5m/s²

Using equation of motion

v²-u²=2as

0-25²=2*-0.5*s

-625=-s

s=625m

Therefore the distance covered by the train before coming to rest will be 625m