Question

A train is travelling at a speed of 90km\hr brakes are applied so as to reduce unifrom acceleration of -0.5m\sec find how for train will go before it is brot to rest.
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Answer 1

it will take 5 seconds
90*5/18 = 25m/sec
25/5 = 5

Answer 2

u= 90km/h

= 25m/s

a= (-0.5) m/s^2

v=0

${v}^{2} = {u}^{2} + 2as$

0= 625 + (-s)

-s = -625

Distance travelled= 625m