Question

a train is travelling at a speed of 90km/hr breakes are applied so as to produce a uniform acceleration of 0.5ms² find how far the train will go before it?​

Answer 1

u= 90 kmper hr

change units to m/s

so u = 90× 5÷ 18= 25 m/s

v= o

a= 0.5m/s2

using formula

v2= u2 +2as

v is zero so

- u2= 2as

(25×25) =2×0.5×s

s=625m