Question

a train is travelling at a speed of 90km/hr . breaks are applied so as to produce uniform acceleration of -0.5m/s². find how far the train will go before it is bought to rest.
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Answer 1

Distance, s = 520.8 m

Explanation:

It is given that,

Initial speed of train, u = 90 km/h = 25 m/s

When brakes are applied, the uniform acceleration of the train is -0.6 m/s². We have to find the distance covered by the train before it come to rest.

Using third equation of motion :

s = 520.8 m

So, the train will go 520.8 m before coming to rest. Hence, this is the required solution.

Answer 2

Answer:

625m

Explanation:

plz refer to the attachment above