A train is travelling at a speed of 90km/hr breaks are applied to produce uniform acceleration -0.5m/s square find how far will the train go before it is brought to rest
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ANS. 625m
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first 90 km/hr to m/s after that apply the formula of accelaration v-u/t and calculate the time after that calculate the distance by s=ut + 1/2 at^2
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