Question

a train is travelling at a speed of 90km per hour brakes are applied to produse a uniform accelaretion -0.5meter pr second squar. find how far will train will the train go brfore it is got nto rest

Answer 1

Answer:

Initial speed, u = 90 km/h = 90 x (1000/3600) m/s = 25 m/s

final speed, v = 0 m/s

uniform acceleration, a = -0.5 m/s2

Using equation of motion: v2 = u2 + 2as

We have: 0 = (25)2 + 2x(-0.5)xs

s = 625 m

[s: distance traveled by the train after the brakes are applied and before it is finally brought into rest]

Answer 2

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Initial speed, u = 90 km/h = 90 x (1000/3600) m/s = 25 m/s

final speed, v = 0 m/s

uniform acceleration, a = -0.5 m/s2

Using equation of motion: v2 = u2 + 2as

We have: 0 = (25)2 + 2x(-0.5)xs

s = 625 m

[s: distance traveled by the train after the brakes are applied and before it is finally brought into rest]