Question

A train is travelling at a speed of 90kmh^-1 brakes are applied so as to produce a uniform acceleration of
0.5ms. Find how far the train will 90 before it is brought to rest.​

Answer 1

Explanation:

THIS IS VERY SIMPLE.

WE KNOW THAT IT HAS A UNIFORM ACCELERATION SO THE ACCELERATION VALUE WILL NOT CHANGE.

USING THE EQUATION OF MOTION WE KNOW THAT

V²=U² + 2AS

(V = FINAL VELOCITY, u= INITIAL VELOCITY AND A = ACCELERATION, S= DISPLACEMENT)

Finding the FINAL VELOCITY

u- Acceleration × Time

90 - 0.5 × 90

90 - 45 = 45

V = 45

NOW PUTTING THE VALUES,

V²=U² + 2AS

45²=90² + 2 × 0.5 × S

2025= 8100 ×S

MULTIPLYING S WITH 2025

2025S = 8100

S = 8100 / 2025

S= 4Km