Question

A train is travelling at an average speed of 90
km/h. If a train left at 10:00 a.m. from station A
then arrival time oftrain at station B which is 60
km away is​

Answer 1

Answer:

Let distance from A to B=x  km= distance from B to A.

Time taken by train from A to B =60x hr 

Time taken by train  from B to A =80x hr

Total time taken by train =60x+80x=2407x hr

average speed=total timetotal distance=2407x2x=7480 km h−1

Explanation:

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Answer 2

Answer: Arrival time of train at station B is 10:40 AM

Explanation:

Speed is defined as rate of travelling. Higher the speed, more is the distance covered in less time.

Distance, time and speed are related by the formula :

Distance = Speed × Time

Distance between station A and station B = 60 km

Average speed of train   = 90 km/h

Time taken for train to reach station B from station A =  Distance ÷ Speed

Time taken for train to reach station B from station A =  60 ÷ 90 h

Time taken for train to reach station B from station A  =  $\frac{2}{3}$ h

Time taken for train to reach station B from station A  =  $\frac{2}{3} * 60$  min

Time taken for train to reach station B from station A  = 40 min

The train covers journey from station A to station B in 40 minutes.

Arrival time at station B = Departure time at station A + Journey time

Arrival time at station B =  10:00 a.m.   +   40 min

Arrival time at station B =  10 : 40 a.m.

The train leaving station A at 10:00 a.m. reaches station B at 10:40 a.m.

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